#985

Sum of Even Numbers After Queries

pupil · 590 · lc medium +29 · verified · 68.8% accepted · 2,137 likes · top 76%

Description

Given integer array nums and query array where each queries[i] = [val, index], process queries in order: add val to nums[index], then capture the current sum of all even-valued elements. Return the array of captured sums.

Example 1:

Input: nums = [1,2,3,4], queries = [[1,0],[-3,1],[-4,0],[2,3]]

Output: [8,6,2,4]

Explanation: At the beginning, the array is [1,2,3,4].

After adding 1 to nums[0], the array is [2,2,3,4], and the sum of even values is 2 + 2 + 4 = 8.

After adding -3 to nums[1], the array is [2,-1,3,4], and the sum of even values is 2 + 4 = 6.

After adding -4 to nums[0], the array is [-2,-1,3,4], and the sum of even values is -2 + 4 = 2.

After adding 2 to nums[3], the array is [-2,-1,3,6], and the sum of even values is -2 + 6 = 4.

Example 2:

Input: nums = [1], queries = [[4,0]]

Output: [0]

Code

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class Solution:
    def sumEvenAfterQueries(self, nums: List[int], queries: List[List[int]]) -> List[int]:

class Solution:
    def sumEvenAfterQueries(self, nums: List[int], queries: List[List[int]]) -> List[int]: