#543

Diameter of Binary Tree

pupil · 335 · lc easy +22 · verified · 65.1% accepted · 15,568 likes · top 69%

⚑ Tree DP ⚑ Tree Path Sum / Maximum Path

Description

Given the root of a binary tree, return the tree's diameter — the number of edges along the longest path connecting any two nodes. This path does not need to go through the root.

Example 1:

Input: root = [1,2,3,4,5]

Output: 3

Explanation: 3 is the length of the path [4,2,1,3] or [5,2,1,3].

Example 2:

Input: root = [1,2]

Output: 1

Code

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def diameterOfBinaryTree(self, root: Optional[TreeNode]) -> int:

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def diameterOfBinaryTree(self, root: Optional[TreeNode]) -> int: