#3379

Transformed Array

newbie · 290 · lc easy +20 · 70.4% accepted · 448 likes · top 79%

Description

You are given an integer array nums representing a circular array. Build a new array result of the same length using these rules for each index i (independently):

- If nums[i] > 0: start at index i, move nums[i] positions to the right (circularly), and set result[i] to the element at the landing index.

- If nums[i] < 0: start at index i, move abs(nums[i]) positions to the left (circularly), and set result[i] to the element at the landing index.

- If nums[i] == 0: set result[i] to nums[i].

Return result.

Note: moving past the last element wraps to the front, and moving before the first element wraps to the back.

Code

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class Solution:
    def constructTransformedArray(self, nums: List[int]) -> List[int]:

class Solution:
    def constructTransformedArray(self, nums: List[int]) -> List[int]: