#3194

Minimum Average of Smallest and Largest Elements

newbie · 130 · lc easy +13 · 85.3% accepted · 204 likes · top 96%

⚑ Converging Pointers (Pair / Triple Sum)

Description

Start with an empty floating-point array averages. You are given an integer array nums of even length n.

Repeat the following n / 2 times:

- Remove the smallest element minElement and the largest element maxElement from nums.

- Append (minElement + maxElement) / 2 to averages.

Return the minimum value in averages.

Code

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class Solution:
    def minimumAverage(self, nums: List[int]) -> float:

class Solution:
    def minimumAverage(self, nums: List[int]) -> float: