#3147

Taking Maximum Energy From the Mystic Dungeon

specialist · 700 · lc medium +30 · 61% accepted · 588 likes · top 61%

Description

An array energy of n values represents magicians in a line (some values may be negative). Choose any starting index; you must collect that magician's energy, then jump to index (start + k), then (start + 2k), and so on until out of bounds. Return the maximum total energy collectible over all starting choices.

Code

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class Solution:
    def maximumEnergy(self, energy: List[int], k: int) -> int:

class Solution:
    def maximumEnergy(self, energy: List[int], k: int) -> int: