#303

Range Sum Query - Immutable

pupil · 315 · lc easy +21 · 71.5% accepted · 3,810 likes · top 80%

Description

Given an integer array nums, support repeated range-sum queries.

Implement the NumArray class:

- NumArray(int[] nums) Initializes the object with the integer array nums.

- int sumRange(int left, int right) Returns the sum of the elements of nums between indices left and right inclusive (i.e. nums[left] + nums[left + 1] + ... + nums[right]).

Example 1:

Input

["NumArray", "sumRange", "sumRange", "sumRange"]

[[[-2, 0, 3, -5, 2, -1]], [0, 2], [2, 5], [0, 5]]

Output

[null, 1, -1, -3]

Example 2:

Explanation

NumArray numArray = new NumArray([-2, 0, 3, -5, 2, -1]);

numArray.sumRange(0, 2); // return (-2) + 0 + 3 = 1

numArray.sumRange(2, 5); // return 3 + (-5) + 2 + (-1) = -1

numArray.sumRange(0, 5); // return (-2) + 0 + 3 + (-5) + 2 + (-1) = -3

Code

class NumArray:

    def __init__(self, nums: List[int]):
        

    def sumRange(self, left: int, right: int) -> int:
        


# Your NumArray object will be instantiated and called as such:
# obj = NumArray(nums)
# param_1 = obj.sumRange(left,right)

class NumArray:

    def __init__(self, nums: List[int]):
        

    def sumRange(self, left: int, right: int) -> int:
        


# Your NumArray object will be instantiated and called as such:
# obj = NumArray(nums)
# param_1 = obj.sumRange(left,right)