#284
Peeking Iterator
specialist · 740 · lc medium +31 · 61.3% accepted · 1,909 likes · top 61%
Description
Extend an existing iterator with a peek operation alongside hasNext and next.
Implement the PeekingIterator class:
- PeekingIterator(Iterator<int> nums) Wraps the given integer iterator iterator.
- int next() Returns the next element and advances the iterator.
- boolean hasNext() Returns true if more elements remain.
- int peek() Returns the next element without advancing the iterator.
Note: Each language may have a different implementation of the constructor and Iterator, but they all support the int next() and boolean hasNext() functions.
Example 1:
Input
["PeekingIterator", "next", "peek", "next", "next", "hasNext"]
[[[1, 2, 3]], [], [], [], [], []]
Output
[null, 1, 2, 2, 3, false]
Example 2:
Explanation
PeekingIterator peekingIterator = new PeekingIterator([1, 2, 3]); // [1,2,3]
peekingIterator.next(); // return 1, the pointer moves to the next element [1,2,3].
peekingIterator.peek(); // return 2, the pointer does not move [1,2,3].
peekingIterator.next(); // return 2, the pointer moves to the next element [1,2,3]
peekingIterator.next(); // return 3, the pointer moves to the next element [1,2,3]
peekingIterator.hasNext(); // return False
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