#2443

Sum of Number and Its Reverse

specialist · 940 · lc medium +32 · verified · 49.4% accepted · 279 likes · top 36%

Description

Given a non-negative integer num, return true if there exists a non-negative integer x such that x + reverse(x) == num, where reverse(x) is the integer obtained by reversing the digits of x.

Example 1:

Input: num = 443

Output: true

Explanation: 172 + 271 = 443 so we return true.

Example 2:

Input: num = 63

Output: false

Explanation: 63 cannot be expressed as the sum of a non-negative integer and its reverse so we return false.

Example 3:

Input: num = 181

Output: true

Explanation: 140 + 041 = 181 so we return true. Note that when a number is reversed, there may be leading zeros.

Code

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class Solution:
    def sumOfNumberAndReverse(self, num: int) -> bool:

class Solution:
    def sumOfNumberAndReverse(self, num: int) -> bool: