#2432
The Employee That Worked on the Longest Task
pupil · 455 · lc easy +26 · verified · 51.4% accepted · 294 likes · top 40%
Description
There are n employees with IDs 0 to n - 1. You are given a 2D array logs where logs[i] = [idi, leaveTimei], meaning employee idi finished the ith task at time leaveTimei. Each task started exactly when the previous ended (task 0 started at time 0). All leaveTime values are unique.
Return the ID of the employee who worked on the single longest task. If there is a tie, return the employee with the smaller ID.
Example 1:
Input: n = 10, logs = [[0,3],[2,5],[0,9],[1,15]]
Output: 1
Explanation:
Task 0 started at 0 and ended at 3 with 3 units of times.
Task 1 started at 3 and ended at 5 with 2 units of times.
Task 2 started at 5 and ended at 9 with 4 units of times.
Task 3 started at 9 and ended at 15 with 6 units of times.
The task with the longest time is task 3 and the employee with id 1 is the one that worked on it, so we return 1.
Example 2:
Input: n = 26, logs = [[1,1],[3,7],[2,12],[7,17]]
Output: 3
Explanation:
Task 0 started at 0 and ended at 1 with 1 unit of times.
Task 1 started at 1 and ended at 7 with 6 units of times.
Task 2 started at 7 and ended at 12 with 5 units of times.
Task 3 started at 12 and ended at 17 with 5 units of times.
The tasks with the longest time is task 1. The employee that worked on it is 3, so we return 3.
Example 3:
Input: n = 2, logs = [[0,10],[1,20]]
Output: 0
Explanation:
Task 0 started at 0 and ended at 10 with 10 units of times.
Task 1 started at 10 and ended at 20 with 10 units of times.
The tasks with the longest time are tasks 0 and 1. The employees that worked on them are 0 and 1, so we return the smallest id 0.
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