#2326

Spiral Matrix IV

pupil · 415 · lc medium +25 · verified · 82.3% accepted · 1,314 likes · top 94%

Description

You are given two integers m and n representing matrix dimensions, and the head of a linked list of integers.

Create an m x n matrix filled with the linked list values in clockwise spiral order starting from the top-left. Any remaining cells are set to -1.

Return the resulting matrix.

Example 1:

Input: m = 3, n = 5, head = [3,0,2,6,8,1,7,9,4,2,5,5,0]

Output: [[3,0,2,6,8],[5,0,-1,-1,1],[5,2,4,9,7]]

Explanation: The diagram above shows how the values are printed in the matrix.

Note that the remaining spaces in the matrix are filled with -1.

Example 2:

Input: m = 1, n = 4, head = [0,1,2]

Output: [[0,1,2,-1]]

Explanation: The diagram above shows how the values are printed from left to right in the matrix.

The last space in the matrix is set to -1.

Code

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def spiralMatrix(self, m: int, n: int, head: Optional[ListNode]) -> List[List[int]]:

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def spiralMatrix(self, m: int, n: int, head: Optional[ListNode]) -> List[List[int]]: